What does this error message means - Warning: Supplied argument is not a valid MySQL result resource and how do you solve it?

I think you got this message from PHP.

You get this message when you are trying to access $result variable, but there is nothing in this variable because of WRONG SQL command before.

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How do I delete a table from a database?

Use this SQL command : "DROP TABLE yourtablename"

What are the differences between GROUP BY and ORDER BY... The manual is not clear on this

GROUP BY is a way to sub-total your results, or perform some other "aggregate" function on them....

Select statement to join tables?

For a simple join: SELECT a.*, b.*FROM tblAlpha a, tblBeta bWHERE (a.keyfield = b.foreignkey);...

I'm new to MySQL, where should I start?

The best source of MySQL information is the excellent on-line manual : ...

Do you provide phpMyAdmin web interface to manage the MySQL Database?

Yes, we provide that. You can login to DotNetPanel first Create MySQL Database, create MySQL...